which consumes more fuel?
#1
which consumes more fuel?
This might be a dumb question but for some reaon i can rationalize both ways so i must ask others opinions.
with overdrive off at lets say 60 mph, rpms 2400, my juice says load on engine is 23%.
while in overdrive, at 60 mph, rpms 1600, juice says load is 35%
which of these scenarios will burn more fuel over an extended period? these speeds/rpms may not be exactly what my truck runs, but i think its close.
just looking at if the "load" reading affects the overall fuel economy? Or am i just to worry about the RPM's?
with overdrive off at lets say 60 mph, rpms 2400, my juice says load on engine is 23%.
while in overdrive, at 60 mph, rpms 1600, juice says load is 35%
which of these scenarios will burn more fuel over an extended period? these speeds/rpms may not be exactly what my truck runs, but i think its close.
just looking at if the "load" reading affects the overall fuel economy? Or am i just to worry about the RPM's?
#2
It depends on the efficiency of the motor at a given RPM and load. My “shooting from the hip” opinion would be the 1600-RPM and 35% load in your example. I’m sure the Cummins engineers could run the numbers for you. 1600-RPM at 90% load might be a different story, however.
#3
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In overdrive at 1600 rpm is more efficient imo. 1600 rpm is right at peak torque, hence, more torque for the amount of fuel injected into each cylinder = more efficiency.
Although, 0.23 x 2400 = 552 and 0.35 x 1600 = 560. Not sure how accurate the Juice is though..
I don't know if my equation is correct but my reasoning behind it is this... If you were at 100% at both rpms, then obviously you'd burn more fuel turning 2400 rpms constant. If you at 50%, you'd still burn more fuel at 2400 rpm than 1600. So if you multiply the numbers, you can see which yields a higher number (more fuel burned). This is assuming that the "load reading" the juice gives you is directly proportional to how much fuel is injected.
Although, 0.23 x 2400 = 552 and 0.35 x 1600 = 560. Not sure how accurate the Juice is though..
I don't know if my equation is correct but my reasoning behind it is this... If you were at 100% at both rpms, then obviously you'd burn more fuel turning 2400 rpms constant. If you at 50%, you'd still burn more fuel at 2400 rpm than 1600. So if you multiply the numbers, you can see which yields a higher number (more fuel burned). This is assuming that the "load reading" the juice gives you is directly proportional to how much fuel is injected.
#4
when there is more of a load, the egt's rise. this leads me to believe the engine is fueling to keep the speed up. this is of course at the lower rpms. thsi is why i am having a hard time figuring it out.
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